- Algebraic expressions are classified on the basis of number of terms.

Various types of algebraic expressions are as follows:

**Monomial:**An expression which has only one term is called monomial.

Eg. \(4x,\; 3y,\; 6z\), etc.

**Binomial:**An expression which has two terms is called binomial.

Eg. \(x^2+4x,\;y+4,\;3x+4\), etc.

**Trinomial:**An expression which has three terms is called trinomial.

Eg. \(x^3+2x+1,\;a^2+b^2+2ab\), etc.

**Quadrinomial:**An expression which has four terms is called quadrinomial.

Eg. \(x^2-y^2+6+x,\;x^3+3+6x^2+2x\), etc.

**Polynomial:**An expression which has two or more than two terms is called polynomial.

Eg. \(6x^3+x^5+x^4+x^2+x+1\), etc.

- If two expressions are equal, they are called equivalent expressions.
- To find the equivalent expression, keep the following rules in mind:

**Commutative Property of Addition:**On changing the order of numbers, their sum does not change. This is known as commutative property of addition, i.e.

\(a+b=b+a\)

** ** 2.** Commutative Property of Multiplication: **On changing the order of numbers, their product does not change. This is known as commutative property of multiplication, i.e.

\(a×b=b×a\)

** ** 3.** Associative Property of Addition:** On changing the grouping of numbers, their sum does not change. This is known as associative property of addition, i.e.

\(a+(b+c)=(a+b)+c\)

** **4**. Associative Property of Multiplication: **On changing the grouping of numbers, their product does not change. This is known as associative property of multiplication, i.e.

\(a×(b×c)=(a×b)×c\)

** ** 5.** Distributive Property of Multiplication over Addition: **The distributive property of multiplication over addition states that multiplying a sum by a number gives the same result as multiplying each addend by the number and then adding the product together, i.e.

\(a(b+c)=a×b+a×c\)

** ** 6.** Distributive Property of Multiplication over Subtraction: **The distributive property of multiplication over subtraction is like the distributive property over addition. Either we find out the difference first and then multiply, or we first multiply with each number and then subtract, the result will always be same, i.e.

\(a(b-c)=ab-ac\)

7. Like terms can be added and subtracted.

- 'Evaluating an expression' means simplifying an expression down to a single numerical value.
- An expression can be evaluated by putting the given value of the variable in the expression and then solving it.
- Here, we will learn how to evaluate an expression when the value of the variable is given.

**For ****example:**

Evaluate: \(4s^2\) when \(s=2\)

Here, the variable is \(s\) and its value is given.

Thus, to evaluate, we simply put \(2\) in place of \(s\).

\(4s^2\)

\(=4(2)^2\)

\(=4×4\)

\(=16\)

A \(6x^2+6xy+6x^2y\)

B \(xy+xy+6x\)

C \(6x+6y+6xy\)

D \(x+y+xy\)

- 'Evaluating an expression' means simplifying an expression down to a single numerical value.
- An expression can be evaluated by putting the given value of variables in the expression and then solving it.
- Here, we will learn how to evaluate an expression when values of two variables are given.

**For example:**

Evaluate: \(a^2b\) for \(a = - 2,\,b=3\)

Here, the variables are \(a\) and \(b\) and their values are given.

Thus to evaluate, we simply put \(-2\) and \(3\) in place of \(a\) and \(b\), respectively.

\(a^2b\)

\(=(-2)^2(3)\)

\(= 4×3\)

\(=12\)

- Here, we will learn how to evaluate a polynomial expression when the value of the variable (or variables) is given.

**For example:**

Evaluate: \(x^2+2xy+y^2\) for \(x=1,\,y=2\)

Here, two variables are used and their values are given.

Thus to evaluate, we simply put the values in place of variables.

\(x^2+2xy+y^2\)

\(=(1)^2+2(1)(2)+(2)^2\)

\(=1+2×2+4\)

\(=1+4+4\)

\(=9\)

- We know that an expression can have multiple operations.
- Here, we will learn to write expressions involving multiple operations.

**For example:**

Jillian's father is thrice as old as Jillian. Two times the sum of their ages is the age of Jillian's grandfather. Write the expression for the grandfather's age.

Here, we first assume that Jillian's age is \(x\) years. Then, her father's age will be \(3x\) years.

Two times the sum of their ages \((x+3x)\) is grandfather's age.

Thus, grandfather's age is \(2(x+3x)\).

A \(45a-20-10\)

B \(10a-45-20\)

C \(20a-45-10\)

D \(45a\)

A \(3(b+c)\)

B \(a^2 + 2ab\)

C \(a^2+2ab+3b+3c\)

D \(a^2+2ab+3b\)