Factors are referred to as the numbers which are being multiplied.
Product refers to the result of a multiplication problem.
Steps:
Suppose, we want to multiply \(2.4\) by \(6.2\).
Write one decimal number just below the other decimal number.
Here, \(6.2\) is the multiplier because it is being multiplied and \(2.4\) is the multiplicand.
First, we multiply each digit of the multiplicand by \(2\).
We multiply \(2\) by \(4\).
\(2×4=8\)
and \(2\) by \(2\)
\(2×2=4\)
Now, we multiply each digit of the multiplicand by \(6\).
\(6×4=24\)
\(4\) is written after placing \(0\) in the second row as we are multiplying by a number in the tens place and \(20\) is carried to \(2\).
Now, \(6×2=12\) and \(2+12=14\)
Here, we are adding \(2\) and not \(20\), because we are already dealing with tens column.
Now, add the products of the given numbers.
In the given example, both decimal numbers have one decimal digit each, both the numbers together have two decimal digits. Therefore, the product will also have two decimal digits.
So, \(14.88\) is the product of \(2.4\) and \(6.2\) .
Factors are referred to as the numbers which are being multiplied.
Product refers to the result of a multiplication problem.
In the multiplication of decimals up to hundredths place, there are two digits after the decimal point in both the factors. Thus, both the numbers together have four decimal digits. Therefore, the product will also have four decimal digits.
Steps:
For example: We want to multiply \(7.35\) by \(2.50\).
Write one decimal number below the other decimal number.
\(\begin{array} {r l} 7.35 & \rightarrow\text{Multiplicand} \\ \times2.50 & \rightarrow\text{Multiplier} \\ \hline & \\ \hline \end{array}\)
Multiply each digit of the multiplier by each digit of the multiplicand, one at a time.
First, we multiply \(735\) by \(0\).
\(735×0=000\)
Multiply \(735\) by \(5\).
\(735×5=3675\)
Now, multiply \(735\) by \(2\).
\(735×2=1470\)
Now, we add the products.
\(\begin{array} {r l} 7.35 & \rightarrow\text{Multiplicand} \\ \times2.50 & \rightarrow\text{Multiplier} \\ \hline 000 \\ 36750 & \rightarrow\text{We add in a zero as we are multiplying by a number at the tens place} \\ +147000 &\rightarrow\text{We add in two zeros as we are multiplying by a number at the hundreds place} \\ \hline 183750 \\ \hline \end{array}\)
In the given example, both the decimal numbers have two decimal digits. Thus, there are altogether four decimal digits. Therefore, the product will also have four decimal digits.
\(18.3750\)
Hence, \(18.375\) is the product of \(7.35\) and \(2.50\)
Factors are referred to as the numbers which are being multiplied.
Product refers to the result of a multiplication problem.
In the multiplication of mixed decimal digits, if there are two digits after the decimal point in the one factor and one digit in the other factor, then all the digits together have three decimal digits. Therefore, the product will also have three decimal digits.
Steps:
Suppose, we want to multiply \(2.7\) by \(0.15\)
Write one decimal number below the other decimal number.
\(\begin{array} {r l} 2.7 & \rightarrow\text{Multiplicand} \\ \times 0.15 & \rightarrow\text{Multiplier} \\ \hline & \\ \hline \end{array}\)
Multiply each digit of the multiplicand by each digit of the multiplier, one at a time.
First, multiply \(27\) by \(5\).
\(27×5=135\)
Multiply \(27\) by \(1\).
\(27×1=27\)
Now, multiply \(27\) by \(0\).
\(27×0=00\)
Now, we add all the products.
\(\begin{array} {r l} 27 & \rightarrow\text{Multiplicand} \\ \times 015 & \rightarrow\text{Multiplier} \\ \hline ^\underline{\color{red}1}135 \\ 270 & \rightarrow\text{We add in a zero as we are multiplying by a number at the tens place} \\ +0000 &\rightarrow\text{We add in two zeros as we are multiplying by a number at the hundreds place} \\ \hline 0405 \\ \hline \end{array}\)
In the given example, the first factor has one decimal digit and the second factor has two decimal digits. Thus, all the numbers together have three decimal digits. Therefore, the product will also have three decimal digits.
\(0.405\)
Hence, \(0.405\) is the product of \(2.7\) and \(0.15\)
Shaded area is \(0.35\) or \(35\) hundredths.
Here, the yellow shaded squares represent the product of \(0.7\) and \(0.5\)
Thus, \(0.7×0.5=0.35\)
Since, \(2.7=2.70=270\) hundredths \(=(100+100+70)\)
So, shade two whole hundred grids and \(70\) squares out of \(100\).
So, shade three whole hundred grids and \(20\) squares out of \(100\).
\(6+2.1+0.4+0.14=8.64\)