In addition:
If both numbers have two zeros, then write two zeros in the sum and add the remaining digits.
In subtraction:
If both numbers have two zeros, then write two zeros in the difference and subtract the remaining digits.
Example: Add \(50,000\) with \(90,000\)
\(\begin {array}\ &9&0&0&0&0\\ +&5&0&0&0&0\\ \hline\\ \hline \end {array}\)
\(\begin {array}\ &9&0&0&0&0\\ +&5&0&0&0&0\\ \hline\\ \hline \end {array}\)
\(\begin {array}\ &9&0&0&0&0\\ +&5&0&0&0&0\\ \hline &&0&0&0&0\\ \hline \end {array}\)
\(9+5=14\)
Therefore,
\(\begin {array}\ &9&0&0&0&0\\ +&5&0&0&0&0\\ \hline 1&4&0&0&0&0\\ \hline \end {array}\)
For example: Solve \(2515+3476\)
We need to line up the digits according to their place values and then add vertically.
Thus, sum of \(2515\) and \(3476\) is \(5991\) as shown.
For example: Subtract \(223\) from \(518\)
\(\begin{array}\\ &&5&1&8\\ &-&2&2&3\\ \hline\\ \end{array}\)
Here, 2 is greater than \(1\) in the tens column, so we borrow from digit \(5\) in hundreds column, that make \(1\)into a \(11\) and \(5\) into \(4\).
Example1: Multiply \(224\) by \(8\)
Example 2: \(517×32\)
We need to line up the digits according to their place values.
First multiply each digit of multiplicand by 2.
Example 1: Divide \(9189\) by \(9\).
Example 2: Divide \(27725\) by \(25\).
Example 3: Divide \(38745\) by \(315\).
So, \(123\) is the Quotient.
4. Division of whole numbers:
For example: Divide \(9189\) by \(9\)
Example 2: Divide \(27725\) by \(25\)
Example 3: Divide \(38745\) by \(315\)
So, \(123\) is the Quotient.
In multiplication:
For example, multiply \(300\) by \(20\)
\(3×2=6\)
\(3\underbrace{00}_{2\text{ zeros}}×2\underbrace{0}_{1 \text{ zero}}=6\underbrace{000}_{\text{Total 3 zeros}}\)
In Division:
For example, divide \(90000\) by \(300\)
First, remove the common zeros.
Since, the numbers have two zeros common, we remove these zeros.
\(\therefore\;90000\div300\)
\(=900\div3\)
Now, divide the remaining digits.
\(900\div3=300\)
A \(50,000\)
B \(500,000\)
C \(5,000,000\)
D \(5,000\)